y=x2y=x^2y=x2在(1,1)处的切线的斜率
∀ε>0\forall \varepsilon >0∀ε>0,∃δ>0,x∈(a−δ,a+δ)⇒∣f(x)−b∣<ε\exist \delta > 0,x \in (a-\delta,a+\delta) \Rightarrow \left| f(x)-b \right| < \varepsilon ∃δ>0,x∈(a−δ,a+δ)⇒∣f(x)−b∣<ε
limx→af(x)=b\lim \limits_{x \to a} f(x) = bx→alimf(x)=b
hugo